(4x^3+11x^2+9)/(x+3)=0

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Solution for (4x^3+11x^2+9)/(x+3)=0 equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(4*x^3+11*x^2+9)/(x+3) = 0

4*x^3+11*x^2+9 = 0

4*x^3+11*x^2+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

4*x^3+11*x^2+9 = 24

1

-1

x = -1

4*x^3+11*x^2+9 = 16

-1

3

x = 3

4*x^3+11*x^2+9 = 216

3

-3

x = -3

4*x^3+11*x^2+9 = 0

-3

x+3

4*x^2-x+3

4*x^3+11*x^2+9

x+3

-4*x^3-12*x^2

9-x^2

x^2+3*x

3*x+9

-3*x-9

0

4*x^2-x+3 = 0

DELTA = (-1)^2-(3*4*4)

DELTA = -47

DELTA < 0

x in { -3} 

x+3 = 0

1 = 0

x belongs to the empty set

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